Table of Contents
The results of CSIR-UGC-NET June 2024 will be declared by 15th October 2024 as Human Resource Development Group or HRDG. a division of CSIR which run various schemes of fellowship, research grants, awards and conduct CSIR NET exam. Almost 9 lakh students are waiting for the announcement of the UGC-NET 2024 exam. The results used to come out a month after the exam took place the June session results are yet to be announced, causing anxiety and stress among students and teachers.
The agency had earlier released provisional answer keys for the exam. Candidates who weren’t pleased with the key had till September 13, 2024 to raise challenges against any answer in the key. For raising challenges against one answer applicants needed to pay a processing fee of Rs 200 per question as non-refundable charges against one answer.
The verification of the challenges made by the candidates will be done by a panel of experts in that particular subject. If any of the challenge by the candidate are found correct, then the experts would revise the response of all the candidates accordingly to fit into the revised final answer key. The results will be prepared and declared as per the above revision. The UGC NET is intended to test the eligibility of a candidate to conduct an assistant professor career and for junior research fellowship and assistant professor in institutions across universities and colleges in India. NTA conducts the CBT examination.
CSIR NET 2024 Application Form: How to Apply
Candidates can fillCSIR NET Online Form 2024for December session as per the steps mentioned below:
Step 1: Register for CSIR NET 2024
To register online, candidates need to follow the steps mentioned below:
- Visit the official website of the exam –csirnet.nta.ac.in
- Click on the link available for filling out the application form
- Click on the ‘New Registration’ button
- Download the CSIR NET information brochure and read the instructions on the page carefully
- Click on the checkbox at the bottom of the page and click on the ‘Click Here to Proceed’ button. On clicking the button theCSIR NET Registration Formwill open on the screen
- Fill in all the given details asked in the registration form
| Personal Details | |
|---|---|
| Name | Father’s name |
| Mother’s name | Date of birth |
| ID type | ID card number |
| Gender | – |
| Contact Details | |
| Complete address | Email ID |
| Mobile number | – |
- Choose a password
- Choose a security question and enter the security answer
- Enter the security pin shown on the screen
- Click on Submit
- Verify the details entered and click on the checkboxes at the end of the page
- Click on the Final Submit button
Step 2: Fill CSIR UGC NET Application Form
| Personal Details | |
|---|---|
| Nationality | Category |
| PwD category | Whether a candidate is diabetic |
| Minority community status | |
| Apply For | |
| Post for which a candidate is applying (JRF and/or Assistant Professor) | Subject opted for CSIR NET |
| Specialisation opted for NET | Exam city preference (four choices in order of priority) |
| Medium of question paper | – |
| Educational Details (of Both Graduation & Post-Graduation) | |
| Pass status | Course/stream name |
| Exam from India/Outside India | University/institute name |
| Year of passing/appearing | Result mode (Percentage/CGPA) |
| Marks details (obtained marks, total marks, obtained percentage) | Date of admission |
| Institute name and address | Institute Pincode |
Step 3: Upload scanned photo and signature
As the next step, candidates need to upload the scanned images of their photo and signature as per the prescribed specifications.
| Document | Format | Size (in KB) |
|---|---|---|
| Photograph | JPG | 10-200 |
| Signature | JPG | 4-30 |
Step 4: Pay CSIR UGC NET application fee
Lastly, candidates need to payCSIR NET 2024 application feein online mode through a debit card/credit card/net banking/UPI/Paytm gateway. The category-wise application fee forCSIR NET 2024is mentioned below.
| Category | CSIR NET Application Fee 2024 (in INR) |
|---|---|
| General | 1,150 |
| OBC – Non-creamy layer | 600 |
| SC/ST/PwD | 325 |
Once the fee is successfully paid, a confirmation page will be generated. Candidates need to print at least three copies of the confirmation page and retain them for future reference.
Details Allowed to be Corrected in CSIR UGC NET Application Form 2024
Candidates can make corrections in the following particulars of theCSIR NET Application Form:
- Candidate name
- Mother name
- Father name
- Educational details
- Candidates address
- Gender
- Date of birth
- Category
- Nationality
- Post applied for
- Subjects opted
- Specialization
- Exam center preference
CSIR NET Eligibility Criteria 2024
The basic CSIR NET Eligibility Criteria that candidates must fulfil are mentioned below:
CSIR NET Educational Qualification 2024
- Candidates should have obtained a degree in BTech/BE/BPharma/MBBS/BS (four years)/Integrated BS-MS/MSc with a minimum of 55 per cent marks for General (UR)/General-EWS and OBC (50 per cent for SC/ST, Third gender and PwD)
CSIR NET Age Limit 2024
- To apply for CSIR NET JRF, candidates should be a maximum of 28 years of age. The upper age limit is relaxable for up to 5 years for SC/ST/Third gender/PwD/Females and up to 3 years for OBC (Non-Creamy Layer)
- There is no upper age limit to apply for the post of Lectureship (LS)/ Assistant Professor
CSIR NET Exam Pattern 2024: Important Points
Candidates can read theCSIR NET Exam Pattern 2024 Important Pointsbelow.
- Questions in Part-A are common for all subjects. This part contains questions on topics/subjects such as logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparison, series formation, puzzles etc.
- Part B of the CSIR UGC NET exam contains subject-related multiple-choice questions. The questions in this part generally cover the topics given in the syllabus
- Questions in Part C test candidates knowledge of scientific concepts and/or application of the scientific concepts. The questions are analytical in nature in which candidates are required to apply scientific knowledge to arrive at the solution to the given problem
- If a candidate attempts more than the required number of questions only the first set of the required questions is considered for scoring
- The CSIR UGC NET question paper is set in both Hindi and English languages
CSIR NET Syllabus 2024
TheCSIR NET Syllabusfor all five subjects is given below:
- Earth, Atmospheric, Ocean and Planetary Sciences
- Chemical Sciences
- Life Sciences
- Mathematical Sciences
- Physical Sciences
CSIR UGC NET Syllabus 2024: Part B & C
The CSIR NET Part B and C syllabus differs subject-wise. Candidates can read the subject-wise CSIR NET Syllabus 2024 in this article. CSIR NET Syllabus for Parts B & C is very crucial for the candidates as this part remains the important factor in the CSIR NET Exam.
CSIR NET Life Science Syllabus 2024
Have a look at Part B and C of the CSIR NET Syllabus for Life Science below. There is a negative marking of 25 per cent for each wrong answer.
- Molecules and their Interaction Relevant to Biology
- Cellular Organization
- Fundamental Processes
- Cell Communication and Cell Signaling
- Developmental Biology
- System Physiology – Plant
- System Physiology – Animal
- Inheritance Biology
- Diversity of Life Forms
- Ecological Principles
- Evolution and Behavior
- Applied Biology
- Methods in Biology
CSIR NET Physical Science Syllabus 2024
Have a look at Part B and C of the CSIR NET syllabus for Physical Science below. There is a negative marking of 25 per cent for each wrong answer.
- Mathematical Methods of Physics
- Classical Mechanics
- Electromagnetic Theory
- Quantum Mechanics
- Thermodynamic and Statistical Physics
- Electronics and Experimental Methods
How to Check CSIR NET Result 2024?
- Step 1:Visit the official website of CSIR NET – csirnet.nta.ac.in
- Step 2:Click on the ‘CSIR UGC NET 2024 Result’ link
- Step 3:Enter the following details:
- Application number
- Date of birth
- Security pin as shown in the image
- Step 4:Click on Submit
- Step 5:View and download the CSIR NET result and scorecard